573 - The Snail
2014-01-18 16:51
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题目:573 - The Snail
题目大意:就是一只蜗牛爬瓶子的故事,给出每天早上爬多少距离,晚上滑多少距离,并且每天都会比前一天少多少距离,求多少天后,蜗牛是在瓶顶,还是平底。
注意:如果U是负数,蜗牛是不会爬负数的距离的。
题目大意:就是一只蜗牛爬瓶子的故事,给出每天早上爬多少距离,晚上滑多少距离,并且每天都会比前一天少多少距离,求多少天后,蜗牛是在瓶顶,还是平底。
注意:如果U是负数,蜗牛是不会爬负数的距离的。
#include<stdio.h> int h,u,d,f; double move ; int day; int main() { while(scanf("%d %d %d %d", &h, &u, &d, &f)&&h) { day = 1; move = 0; double up = u; while(1) { if(up > 0) move += up; if(move > h) { printf("success on day %d\n", day); break; } else if((move - d) < 0) { printf("failure on day %d\n", day); break; } else { day++; move -= d; up -= u * f / 100.0; } } } return 0; }
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