黑马程序员——判断身份证是否合法

例子：判断是否为合法的15位或18位身份证号码

import java.util.regex.Matcher;

import java.util.regex.Pattern;

public class RegexTest {

/**
* @param args
*/
public static void main(String[] args) {

// 测试是否为合法的身份证号码
String[] strs = { "130681198712092019", "13068119871209201x",
"13068119871209201", "123456789012345", "12345678901234x",
"1234567890123" };
Pattern p1 = Pattern.compile("(\\d{17}[0-9a-zA-Z]|\\d{14}[12][0-9]{3}[01][0-9][123][0-9])");
for (int i = 0; i < strs.length; i++) {
Matcher matcher = p1.matcher(strs[i]);
System.out.println(strs[i] + ":" + matcher.matches());
}

Pattern p2 = Pattern.compile("\\d{6}(\\d{8}).*"); // 用于提取出生日字符串
Pattern p3 = Pattern.compile("(\\d{4})(\\d{2})(\\d{2})");// 用于将生日字符串进行分解为年月日
for (int i = 0; i < strs.length; i++) {
Matcher matcher = p2.matcher(strs[i]);
boolean b = matcher.find();
if (b) {
String s = matcher.group(1);
Matcher matcher2 = p3.matcher(s);
if (matcher2.find()) {
System.out.println("生日为" + matcher2.group(1) + "年"
+ matcher2.group(2) + "月"
+ matcher2.group(3) + "日");
}
}

}
}

}