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[Leetcode] Insert Interval (Java)

2014-01-08 19:16 417 查看
Given a set of non-overlapping intervals, insert a new interval into the intervals (merge if necessary).
You may assume that the intervals were initially sorted according to their start times.
Example 1:

Given intervals
[1,3],[6,9]
, insert and merge
[2,5]
in
as
[1,5],[6,9]
.
Example 2:

Given
[1,2],[3,5],[6,7],[8,10],[12,16]
, insert and merge
[4,9]
in
as
[1,2],[3,10],[12,16]
.
This is because the new interval
[4,9]
overlaps
with
[3,5],[6,7],[8,10]
.

插入,感觉考的是ListIterator的用法

/**
* Definition for an interval.
* public class Interval {
*     int start;
*     int end;
*     Interval() { start = 0; end = 0; }
*     Interval(int s, int e) { start = s; end = e; }
* }
*/
import java.util.ListIterator;
public class Solution {
public ArrayList<Interval> insert(ArrayList<Interval> intervals, Interval newInterval) {
Interval temp = new Interval(newInterval.start, newInterval.end);
ListIterator<Interval> iterator = intervals.listIterator();
while(iterator.hasNext()){
Interval interval = iterator.next();
if(temp.end<interval.start){
iterator.previous();
iterator.add(temp);
return intervals;
}
if(temp.start>interval.end)
continue;
temp=new Interval(Math.min(temp.start, interval.start), Math.max(temp.end, interval.end));
iterator.remove();
}
intervals.add(temp);
return intervals;
}
}
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