uva 10025 - The ? 1 ? 2 ? ... ? n = k problem
2014-01-03 15:56
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这题乍看很难,其实一想就通了
只要1+。。+n>=k
这时候要填符号,就是 减去双倍的某个数
所以1+..n减去k必为偶数
只要1+。。+n>=k
这时候要填符号,就是 减去双倍的某个数
所以1+..n减去k必为偶数
#include<iostream> #include<math.h> using namespace std; int main(){ int n; cin>>n; while(n--){ int k; cin>>k; if(k==0){ cout<<3<<endl<<endl; continue; } if(k<0) k=-k; int l=(int)sqrt((double)(2*k)); for(int i=l;;i++){ if((i+1)*i>=2*k&&((i+1)*i/2-k)%2==0){ cout<<i<<endl; break; } } if(n>0) cout<<endl; } }
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