xls 和 xml 数据 排序 绑定 -原创

<?xml version="1.0" encoding="UTF-8"?>
<?xml-stylesheet type= "text/xsl" href= "test.xsl"?>
<!--
To change this license header, choose License Headers in Project Properties.
To change this template file, choose Tools | Templates
and open the template in the editor.
-->
<languages>
<languageList>
<language name="Chinese" >
<codeList >
<code >zh</code>
</codeList>
</language>
<language name="English" >
<codeList >
<code >en</code>
</codeList>
</language>
</languageList>
</languages>

<?xml version="1.0" encoding="UTF-8"?>

<!--
Document   : test.xsl
Created on : 2013年12月26日, 下午9:37
Author     : ideaam
Description:
Purpose of transformation follows.
-->
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output omit-xml-declaration="yes" indent="yes"/>

<xsl:variable name="vsortKey" select="'name'"/>
<xsl:variable name="vsortOrder" select="'descending'"/>

<xsl:template match="node()|@*">
<xsl:copy>
<xsl:apply-templates select="node()|@*">
<xsl:sort select="/language[name()=$vsortKey] | @*[name()=$vsortKey]" data-type="text" order="{$vsortOrder}"/>
<xsl:sort select="@*"  />
</xsl:apply-templates>
</xsl:copy>
</xsl:template>
</xsl:stylesheet>

<asp:ListView ID="ListView1" runat="server" DataSourceID="XmlDataSource1">
<ItemTemplate>
<label><%#Eval("name")%></label>
</ItemTemplate>
</asp:ListView>
<asp:XmlDataSource ID="XmlDataSource1" runat="server" DataFile="~/test.xml"
XPath="//language" TransformFile="~/test.xsl"></asp:XmlDataSource>