LeetCode | Merge Intervals
2013-12-25 16:43
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题目:
Given a collection of intervals, merge all overlapping intervals.For example,
Given
[1,3],[2,6],[8,10],[15,18],
return
[1,6],[8,10],[15,18].
思路:
首先按照start来排序,然后依次合并相邻的重叠项。
代码:
/** * Definition for an interval. * struct Interval { * int start; * int end; * Interval() : start(0), end(0) {} * Interval(int s, int e) : start(s), end(e) {} * }; */ class Solution { public: static bool comp(Interval a, Interval b) { return a.start<b.start; } vector<Interval> merge(vector<Interval> &intervals) { if(intervals.size()==0) return *(new vector<Interval>()); sort(intervals.begin(),intervals.end(),comp); int cur = 0; while(cur<intervals.size()-1) { if(intervals[cur].end>=intervals[cur+1].start) { int s = intervals[cur].start; int e = intervals[cur].end>intervals[cur+1].end?intervals[cur].end:intervals[cur+1].end; intervals.erase(intervals.begin()+cur,intervals.begin()+cur+2); intervals.insert(intervals.begin()+cur,*(new Interval(s, e))); } else { cur++; } } return intervals; } };
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