【SQL Server DBA】维护语句：删除并创建外键约束、获取建表语句

1、删除外键约束，建立外键约束

先建立3个表：

/*
drop table tb
drop table tb_b
drop table tb_c
*/

--建立3个关联的表
create table tb(id int primary key ,vv varchar(10))

create table tb_b(
idd int primary key,
id int foreign key references tb(id)
)

create table tb_c(
iddd int primary key,
idd int foreign key references tb_b(idd)
)
go

可以生成删除外键的语句，需要复制出来，然后放到再执行：

;WITH FK  --外键约束
AS
(
SELECT
SCH.name as foreign_schema_name,   --外键schema名
FK.name as foreign_name,           --外键名
FK.is_disabled ,                   --是否禁用

FK.delete_referential_action_desc as delete_action,
FK.update_referential_action_desc as update_action,

FKC.constraint_column_id,		   --约束列的id
FKC.parent_object_id,              --父对象的id
FKC.parent_column_id,              --父对象列的id

FKC.referenced_object_id,          --被引用的对象
FKC.referenced_column_id           --被引用的对象中的列
FROM sys.foreign_keys FK
INNER JOIN sys.foreign_key_columns FKC
ON FK.object_id = FKC.constraint_object_id
INNER JOIN sys.schemas SCH
ON FK.schema_id = SCH.schema_id
),

TB   --表和列
AS
(
SELECT
TB.object_id,
SCH.name as schema_name,
TB.name as table_name,
C.column_id as column_id,
C.name as column_name
FROM sys.tables TB WITH(NOLOCK)
INNER JOIN sys.columns C WITH(NOLOCK)
ON TB.object_id = C.object_id
INNER JOIN sys.schemas SCH WITH(NOLOCK)
ON TB.schema_id = SCH.schema_id
WHERE TB.is_ms_shipped = 0  -- 此条件表示仅查询不是由内部 SQL Server 组件创建对象
)

SELECT
'alter table ['+TBP.schema_name+'].['+TBP.table_name+
'] drop constraint ['+FK.foreign_name+'];' as '删除外键的语句,复制出来后运行'
FROM FK
INNER JOIN TB TBP
ON FK.parent_object_id = TBP.object_id
AND FK.parent_column_id = TBP.column_id

INNER JOIN TB TBR
ON FK.referenced_object_id = TBR.object_id
AND FK.referenced_column_id = TBR.column_id
/*
删除外键的语句,复制出来后运行
alter table [dbo].[tb_b] drop constraint [FK__tb_b__id__6754599E];
alter table [dbo].[tb_c] drop constraint [FK__tb_c__idd__6C190EBB];
*/

另外，删除主键后，插入数据，然后再建立外键：

;WITH FK  --外键约束
AS
(
SELECT
SCH.name as foreign_schema_name,   --外键schema名
FK.name as foreign_name,           --外键名
FK.is_disabled ,                   --是否禁用

FK.delete_referential_action_desc as delete_action,
FK.update_referential_action_desc as update_action,

FKC.constraint_column_id,		   --约束列的id
FKC.parent_object_id,              --父对象的id
FKC.parent_column_id,              --父对象列的id

FKC.referenced_object_id,          --被引用的对象
FKC.referenced_column_id           --被引用的对象中的列
FROM sys.foreign_keys FK
INNER JOIN sys.foreign_key_columns FKC
ON FK.object_id = FKC.constraint_object_id
INNER JOIN sys.schemas SCH
ON FK.schema_id = SCH.schema_id
),

TB   --表和列
AS
(
SELECT
TB.object_id,
SCH.name as schema_name,
TB.name as table_name,
C.column_id as column_id,
C.name as column_name
FROM sys.tables TB WITH(NOLOCK)
INNER JOIN sys.columns C WITH(NOLOCK)
ON TB.object_id = C.object_id
INNER JOIN sys.schemas SCH WITH(NOLOCK)
ON TB.schema_id = SCH.schema_id
WHERE TB.is_ms_shipped = 0  -- 此条件表示仅查询不是由内部 SQL Server 组件创建对象
)

SELECT
'alter table ['+TBP.schema_name+'].['+TBP.table_name+
'] add constraint ['+FK.foreign_name+'] '+
' foreign key('+TBP.column_name+') references [' +
TBR.schema_name +'].['+ TBR.table_name +']('+TBR.column_name+')'
as '新建外键索引,复制然后在运行'
FROM FK
INNER JOIN TB TBP
ON FK.parent_object_id = TBP.object_id
AND FK.parent_column_id = TBP.column_id

INNER JOIN TB TBR
ON FK.referenced_object_id = TBR.object_id
AND FK.referenced_column_id = TBR.column_id
/*
新建外键索引,复制然后在运行
alter table [dbo].[tb_c] add constraint [FK__tb_c__idd__0A9D95DB]  foreign key(idd) references [dbo].[tb_b](idd)
alter table [dbo].[tb_b] add constraint [FK__tb_b__id__05D8E0BE]  foreign key(id) references [dbo].[tb](id)
*/

另外，还有一个问题：原来两个表之间是有外键的，删除了外键导入数据后，导入的数据记录条数和原表也一致，发现子表有记录不属于主表的，那么原来的外键是怎么建立的？

create table tb(id int primary key ,vv varchar(10))

insert into tb
values(1,'aa')
go

create table tb_b(
idd int primary key,
id int --foreign key references tb(id)
)

insert into tb_b
values(1,2)  --id不在主表中
go

--新增外键约束,不会报错，with nocheck对于之前已经存在的数据，不会进行检测
ALTER TABLE [dbo].[tb_b]  WITH noCHECK ADD FOREIGN KEY([id])
REFERENCES [dbo].[tb] ([id])
GO

--会报错 ，在建立上面的约束后，再次插入，就会报错了
insert into tb_b
values(2,2)  --id不在主表中

2、如何根据表名查询出创建该表的代码

--当用以下代码创建一个表后，如何根据表名查询出创建该表的代码(也就是以下代码)？
CREATE TABLE [dbo].[a1](
[c2] [decimal](10, 2) NULL,
[c3] [decimal](10, 3) NULL CONSTRAINT [DF_a1_c3]  DEFAULT ((0)),
[re] [bigint] IDENTITY(1,1) NOT NULL,
CONSTRAINT [PK_a1] PRIMARY KEY CLUSTERED
(
[re] ASC
)WITH (PAD_INDEX  = OFF, STATISTICS_NORECOMPUTE  = OFF, IGNORE_DUP_KEY = OFF, ALLOW_ROW_LOCKS  = ON, ALLOW_PAGE_LOCKS  = ON) ON [PRIMARY]
) ON [PRIMARY]
go

declare @sql varchar(8000),@tablename varchar(100)
set @tablename ='a1'--这里输入表名
set @sql = 'create table ['+@tablename+']
(
'
select @sql = @sql + b.name + ' '+
c.name+
case when c.collation_name is not null then '('+
case when b.max_length <>-1 then convert(varchar(100),b.max_length)
else 'MAX'
end +') '
else ''
end +
case when b.is_identity = 1 then ' identity('+convert(varchar(100),IDENT_SEED(@tablename))+','+convert(varchar(100),IDENT_INCR(@tablename))+')' else '' end +
case when d.definition is not null then ' default('+d.definition +')' else '' end +
case when b.is_nullable = 0 then ' not null' else ' null' end +

',
'
from sys.objects a join sys.columns b
on a.object_id = b.object_id
join sys.types c
on b.system_type_id = c.system_type_id and b.user_type_id = c.user_type_id
left join sys.default_constraints d
on b.default_object_id = d.object_id
where a.name=@tablename
order by b.column_id
if exists(select * from sys.indexes where object_id =object_id(@tablename) and is_primary_key =1 )
begin
select @sql = @sql + 'CONSTRAINT ['+name+'] PRIMARY KEY '+type_desc+'
(
' from sys.indexes where object_id =object_id(@tablename) and is_primary_key =1
select @sql = @sql + b.name + case when a.is_descending_key =1 then ' DESC' else ' ASC' end +',
' from sys.index_columns a join sys.columns b
on a.object_id= b.object_id and a.column_id = b.column_id
where a.object_id =object_id(@tablename)
select @sql = left(@sql,len(@sql)-3)+'
)'
select @sql = @sql+'
) ON [PRIMARY] '
end
else
begin
select @sql = left(@sql,len(@sql)-1)+'
) ON [PRIMARY] '
end
print @sql

/*
create table [a1]
(
c2 decimal null,
c3 decimal default(((0))) null,
re bigint identity(1,1) not null,
CONSTRAINT [PK_a1] PRIMARY KEY CLUSTERED
(
re ASC
)
) ON [PRIMARY]

*/