Http请求之--C#的HttpWebRequest实现POST方式请求

1、添加头信息和请求方法。有两种方式添加

req = (HttpWebRequest)WebRequest.Create("http://zhidao.baidu.com/submit/ajax/");

req.Method = "POST";//请求方式是POST
req.Accept = "text/html,application/xhtml+xml,application/xml;q=0.9,*/*;q=0.8";
req.Headers.Add("Accept-Encoding", "gzip, deflate");
req.Headers.Add("Accept-Language", "zh-cn,zh;q=0.8,en-us;q=0.5,en;q=0.3");
req.UserAgent = "Mozilla/5.0 (Windows NT 6.1; rv:25.0) Gecko/20100101 Firefox/25.0";
req.Headers.Add("Cache-Control", "no-cache");
req.Headers.Add("Pragma", "no-cache");
req.ContentType = "application/x-www-form-urlencoded; charset=UTF-8";
req.Referer = textBox1.Text.Trim();
req.Headers.Add("X-Requested-With", "XMLHttpRequest");//这是AJAX请求标志
req.KeepAlive = true;

req.ServicePoint.Expect100Continue = false;//不使用那种行为Continue 100行为，约束请求用的

一种是用Headers来添加，但是只能部分添加，另一种是HttpWebRequest固有属性，如req.KeepAlive等 ；至于到底选择哪种方式呢？有一个原则：能通过一个属性的就用属性，比如KeepAlive表示头部的Connection；UserAgent表示头部的UserAgent等；但是标头键值没有对应的属性时，再用Headers这个集合性质的属性进行添加，如Cache-Control

2、布置要POST的内容（如果是GET方式就不用了）

Stream s = req.GetRequestStream();//注意这里是引用，不是简单的赋值，最开始看到这个还以为是错误呢
string cm="100009";
string qid= textBox1.Text.Trim();
qid = qid.Substring(qid.IndexOf("question/")+9,19);
string title = "";
string answerfr = "";
string entry = "qb_submit";
string cite = "";
string rich = "1";
string utdata = "111,74,112,111,113,111,112,111,113,111,112,111,113,111,112,111,113,111,112,111,113,74,118,122,113,118,119,74,114,114,112,123,111,117,119,115,13848662019671";
string stoken = "4c05d1b485b73ff79dd7f7562ea079c8";
string co="具体我也不是太清楚，可以在网上查一下";
string strdata = "cm=" + cm + "&qid=" + qid + "&title=" + "&answerfr=" + "&entry=" + entry + "&cite=" + "&rich=" + rich +
"&utdata=" + System.Web.HttpUtility.UrlEncode(utdata) + "&co=" + HttpUtility.UrlEncode(co) + "&stoken=" + stoken;//部分内容使用的Url转码
byte[] bytes = Encoding.UTF8.GetBytes(strdata);
s.Write(bytes, 0, bytes.Length);//把请求内容写入到请求对象中，以字节的方式

3、发送请求；只用一个方法

Stream ret=req.GetResponse().GetResponseStream();//得到网络流