android 和 php 简单的数据交互

注意：

1 加入权限：

<uses-permission android:name="android.permission.INTERNET" />

<uses-permission android:name="android.permission.ACCESS_NETWORK_STATE" />

2启动一个新线程

android4.0开始不允许直接在ui线程直接操作httpClient

3 注意url:http://10.0.2.2/testAndroid.php

(不要填写:127.0.0.1 这个是本机电脑的,模拟器有自己的默认ip)

4通过handler将数据从新线程中传送出来

步骤：

1 创建一个httpClient 对象

2 使用post发送数据 创建一个HttpPost对象

3 设置请求参数用setEntity()

4 调用httpClient对象的execute() 发送请求，返回一个HttpResponse

5 调用HttpResponse的getEntity() 方法可以获取HttpEntity 对象

android =============================================

HttpClient client = new DefaultHttpClient();

StringBuilder builder = new StringBuilder();

HttpPost post = new HttpPost("http://10.0.2.2/testAndroid.php");

List<NameValuePair> params = new ArrayList<NameValuePair>();

params.add(new BasicNameValuePair("name","linzhouzhi"));

try {

post.setEntity(new UrlEncodedFormEntity(params,HTTP.UTF_8));

} catch (UnsupportedEncodingException e1) {

e1.printStackTrace();

}

try {

HttpResponse response = client.execute(post);

HttpEntity entity = response.getEntity();

BufferedReader reader = new BufferedReader(new InputStreamReader(entity.getContent()));

for (String s = reader.readLine(); s != null; s = reader.readLine()) {

builder.append(s);

}

JSONObject jsonObject = new JSONObject(builder.toString());

String name = jsonObject.getString("name");

Message msg = new Message();

msg.what = 0x123;

msg.obj = name;

myHandler.sendMessage(msg);

php======================================================

<?php

if($_POST['name']=='linzhouzhi'){

$array = array( 'name'=>'linzhouzhi');

echo json_encode($array);

}else{

$array = array('name'=>'err');

echo json_encode($array);

}

?>