POJ 2013 Symmetric Order (水题)
2013-11-13 19:07
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冲着题号去做的,结果是大水题,就是从小到大输出奇数组,然后从大到小输出偶数组
最近想着流水线就不想用if了,n-1-(n&1)是唯一可说的一点了吧
最近想着流水线就不想用if了,n-1-(n&1)是唯一可说的一点了吧
#include <stdio.h> int main() { int T=1,i=0,n; char data[15][26]; while(scanf("%d\n",&n) && n) { for(i=0;i<n;++i) { gets(data[i]); } printf("SET %d\n",T++); for(i=0;i<n;i+=2) { puts(data[i]); } for(i=n-1-(n&1);i>=0;i-=2) { puts(data[i]); } }
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