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UVA - 10048 Audiophobia

2013-11-08 23:54 411 查看
题意:理解了题解的意思:是求在多条从a到b的路径中,每条路径都要选出它的最大路段,最后在这些路段中选出最小的即可。稍微修改一下Floyd就可以了
#include <iostream>
#include <cstdio>
#include <cstring>
#include <algorithm>
using namespace std;
const int MAXN = 110;
const int INF = 0x3f3f3f3f;

int d[MAXN][MAXN],C,S,Q,cas,flag;

void init(){
    memset(d,INF,sizeof(d));
    for (int i = 1; i <= C; i++)
        d[i][i] = 0;
}

void read(){
    init();
    int u,v,w;
    for (int i = 0; i < S; i++){
        scanf("%d%d%d",&u,&v,&w);
        d[u][v] = d[v][u] = w;
    }
}

void Floyd(){
    for (int k = 1; k <= C; k++)
        for (int i = 1; i <= C; i++)
            for (int j = 1; j <= C; j++)
                d[i][j] = min(d[i][j],max(d[i][k],d[k][j]));
}

void solve(){
    if (flag)
        flag = 0;
    else printf("\n");
    printf("Case #%d\n",cas++);
    int u,v;
    for (int i = 0; i < Q; i++){
        scanf("%d%d",&u,&v);
        if (d[u][v] == INF)
            printf("no path\n");
        else printf("%d\n",d[u][v]);
    }
}

int main(){
    cas = 1;
    flag = 1;
    while (scanf("%d%d%d",&C,&S,&Q) != EOF && C+S+Q){
       read();
       Floyd();
       solve();
    }
    return 0;
}
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