JSP中js传递和解析URL参数以及中文转码和解码问题

1.传递参数：
代码如下:

var pmt = 'sensor='+ encodeURI(encodeURI(sensor))+'&device='+encodeURI(encodeURI(device))+'&instrument=';
pmt += encodeURI(encodeURI(instrument))+'&n='+n+'&addDate='+addDate;
top.location.href = 'jsp/print/diagnosticAnaPrint.jsp?'+pmt;

2.接收和解析参数
代码如下:

//获取URL参数
function GetRequest() {
var url = location.search; //获取url中"?"符后的字串
var theRequest = new Object();
if (url.indexOf("?") != -1) {
var str = url.substr(1);
strs = str.split("&");
for(var i = 0; i < strs.length; i ++) {
theRequest[strs[i].split("=")[0]]=unescape(strs[i].split("=")[1]);
}
}
return theRequest;
}

var sensor;//测点
sensor = decodeURI(decodeURI(Request['sensor']));
3.参考内容：
方法一：正则分析法
代码如下:

function getQueryString(name) {
var reg = new RegExp("(^|&)" + name + "=([^&]*)(&|$)", "i");
var r = window.location.search.substr(1).match(reg);
if (r != null) return unescape(r[2]); return null;
}
这样调用：
alert(GetQueryString("参数名1"));
alert(GetQueryString("参数名2"));
alert(GetQueryString("参数名3"));

方法二：
代码如下:

<span style="font-size: 16px;"><Script language="javascript">
function GetRequest() {
var url = location.search; //获取url中"?"符后的字串
var theRequest = new Object();
if (url.indexOf("?") != -1) {
var str = url.substr(1);
strs = str.split("&");
for(var i = 0; i < strs.length; i ++) {
theRequest[strs[i].split("=")[0]]=unescape(strs[i].split("=")[1]);
}
}
return theRequest;
}
</Script></span>
这样调用：
<Script language="javascript">
var Request = new Object();
Request = GetRequest();
var 参数1,参数2,参数3,参数N;
参数1 = Request['参数1'];
参数2 = Request['参数2'];
参数3 = Request['参数3'];
参数N = Request['参数N'];
</Script>

本文出自 “unity3d学习者” 博客，请务必保留此出处http://unity3d168.blog.51cto.com/4361353/1318591