uva 542 - France '98(概率）

题目链接：uva 542 - France '98

题目大意：有16支球队比赛，给出16支球队的名称，然后给出16*16的表格，g[i][j] 表示i队胜j队的概率，问说16支球队获得总冠军的概率。

解题思路：模拟比赛的过程，将队伍分组，每次和组内的其他队伍决胜负，概率之和即为出现的概率，只要处理好下标就可以了。

#include <stdio.h>
#include <string.h>
#include <math.h>

const int N = 16;
char name[N + 10][N + 10];
double p[N + 10][N + 10];
double ans[N + 10], rec[N + 10];

void init() {
for (int i = 1; i <= N; i++)
scanf("%s", name[i]);

int c;
for (int i = 1; i <= N; i++)
for (int j = 1; j <= N; j++) {
scanf("%d", &c);
p[i][j] = c / 100.0;
}

for (int i = 1; i <= N; i++)
ans[i] = 1;

}

int main () {
int group, tmp, g, s;
init();
for (int i = 0; i < 4; i++) {
group = pow(2, i + 1);
tmp = group / 2;

for (int i = 1; i <= N; i++) {
double c = 0;
g = (i - 1) / group;

if ((i - 1) % group < tmp) {
s = g * group + tmp;

} else {
s = g * group;
}
for (int j = 1; j <= tmp; j++)
c += ans[i] * p[i][j + s] * ans[j + s];
rec[i] = c;
}
memcpy(ans, rec, sizeof(ans));
}

for (int i = 1; i <= N; i++)
printf("%-10s p=%.2lf%c\n", name[i], ans[i] * 100, '%');

return 0;
}