作业 2 分支、循环结构

/*两个整数的四则运算*/

#include<stdio.h>
int main(void)
{
int num1,num2,h,c,j,y;
/*h和，c差，j积，s商，y余数*/
double s;
printf("Enter num1 and num2:");
scanf("%d%d",&num1,&num2);
h=num1+num2;
c=num1-num2;
j=num1*num2;
s=num1/num2;
y=num1%num2;
printf("h=%d,c=%d,j=%d,s=%Lf,y=%d\n",h,c,j,s,y);
return 0;
}

/*计算x的n次方*/

#include<stdio.h>

int main()

{

int n,i;

double x,y;

y=1;

printf("Enter n and x:");

scanf("%d%Lf",&n,&x);

for(i=1;i<=n;i++)

y=y*x;

printf("y=%.2f\n",y);

return 0;

}

/*求i^2+1/i*，i=m~n,求和/

#include<stdio.h>

int main()

{

int m,n,i;

double y;

y=0;

printf("Enter m and n:");

scanf("%d%d",&m,&n);

for(i=m;i<=n;i++)

y=y+(i*i+1.0/i);     //转换类型
printf("y=%.2f\n",y);

return 0;

}

/*计算1-2/3+3/5-4/7+5/9-6/11+^的前n项和*/

#include<stdio.h>

int main()

{

int n,flag;

double item,sum,i;

printf("Enter n:");

scanf("%d",&n);

flag=1;    /*第i项的符号*/

sum=0;

for(i=1.0;i<=n;i++){

item=flag*i/(2*i-1);  /*第n项的值*/

sum=sum+item;

flag=-flag;

}

printf("sum=%f\n",sum);

return 0;

}

/*打印还款年限-月还款额表*/

#include<stdio.h>

#include<math.h>

int main()

{

int loan,month,i,money;

double rate,m,n;

printf("Enter loan and rate:\n");

scanf("%d%Lf",&loan,&rate);

for(i=5;i<=30;i++){

month=i*12;

m=rate*pow(1+rate,month);

n=pow(1+rate,month)-1;

money=loan*(m/n);

printf("i=%d,money=%d\n",i,money);

}

return 0;

}

/*计算2^i,i=1~n,输入n并求和*/

#include<stdio.h>

#include<math.h>

int main(void)

{

int n,i;

double m,sum;

printf("Enter n:");

scanf("%d",&n);

sum=0;

for(i=1;i<=n;i++){

m=pow(2,i);

sum=sum+m;

}

printf("sum=%.2f\n",sum);

return 0;

}