您的位置:首页 > 其它

Path Sum [LeetCode]

2013-10-14 07:51 232 查看
Problem Description: http://oj.leetcode.com/problems/path-sum/

Pretty easy.

/**
* Definition for binary tree
* struct TreeNode {
*     int val;
*     TreeNode *left;
*     TreeNode *right;
*     TreeNode(int x) : val(x), left(NULL), right(NULL) {}
* };
*/
class Solution {
public:
vector<int> getSums(TreeNode *root) {
vector<int> sums;

if(root->left == NULL && root->right == NULL)
sums.push_back(root->val);

if(root->left != NULL){
vector<int> left_sums;
left_sums = getSums(root->left);
for(auto item : left_sums) {
sums.push_back(item + root->val);
}
}

if(root -> right != NULL) {
vector<int> tmp_sums;
tmp_sums = getSums(root->right);
for(auto item : tmp_sums) {
sums.push_back(item + root->val);
}
}

return sums;
}

bool hasPathSum(TreeNode *root, int sum) {
// Note: The Solution object is instantiated only once and is reused by each test case.
if(root == NULL)
return false;

vector<int> sums = getSums(root);

for(auto item : sums) {
if(item == sum)
return true;
}

return false;
}
};
内容来自用户分享和网络整理,不保证内容的准确性,如有侵权内容,可联系管理员处理 点击这里给我发消息
标签: