PAT Basic 1002

#include<stdio.h>
char a[10][5]={"ling","yi","er","san","si","wu","liu","qi","ba","jiu"};
/*递归的从左至右输出各个位*/
void b(int sum,int count)
{
count++;
if(sum/10 !=0 )
b(sum/10,count);
if(count==1)
printf("%s",a[sum%10]);
else
printf("%s ",a[sum%10]);
}

int main()
{
char n[102];
int i=0,sum=0,r=1;
scanf("%s",n);
while(n[i]!='\0')
sum += n[i++]-48 ;
b(sum,0);
return 0;
}