Leetcode: Remove Duplicates from Sorted List
2013-10-04 17:24
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Given a sorted linked list, delete all duplicates such that each element appear only once.
For example,
Given
Given
精简代码:
/**
* Definition for singly-linked list.
* struct ListNode {
* int val;
* ListNode *next;
* ListNode(int x) : val(x), next(NULL) {}
* };
*/
class Solution {
public:
ListNode* deleteDuplicates(ListNode* head) {
if(head == NULL || head->next == NULL) return head;
ListNode* p = head;
ListNode* q = head->next;
while(q){
while(q && q->val == p->val) q = q->next;
p->next = q;
if(q) {p = p->next; q=q->next;}
}
return head;
}
};
For example,
Given
1->1->2, return
1->2.
Given
1->1->2->3->3, return
1->2->3.
/** * Definition for singly-linked list. * struct ListNode { * int val; * ListNode *next; * ListNode(int x) : val(x), next(NULL) {} * }; */ class Solution { public: ListNode *deleteDuplicates(ListNode *head) { // Note: The Solution object is instantiated only once. if(head==NULL)return head; ListNode* pre = head->next; ListNode* p=head; while(pre) { if(p->val == pre->val) { ListNode* tmp = pre; pre = pre->next; p->next = pre; delete tmp; }else{ p = pre; pre=pre->next; } } return head; } };
精简代码:
/**
* Definition for singly-linked list.
* struct ListNode {
* int val;
* ListNode *next;
* ListNode(int x) : val(x), next(NULL) {}
* };
*/
class Solution {
public:
ListNode* deleteDuplicates(ListNode* head) {
if(head == NULL || head->next == NULL) return head;
ListNode* p = head;
ListNode* q = head->next;
while(q){
while(q && q->val == p->val) q = q->next;
p->next = q;
if(q) {p = p->next; q=q->next;}
}
return head;
}
};
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