nyoj 4 ASCII码排序 java

java输入字符：1、String s=sc.next();

2、char a=s.charAt(0);

注意：package java 中提交不能带package

java代码：

import java.util.Scanner;

public class Main {

public static void main(String[] args)
{
Scanner input = new Scanner(System.in);
int n = input.nextInt();
while(n-->0)
{
String string = input.next();
char a = string.charAt(0);
char b = string.charAt(1);
char c = string.charAt(2);

if(a>b){char s=a;a=b;b=s;}
if(a>c){char s=a;a=c;c=s;}
if(b>c){char s=b;b=c;c=s;}

System.out.println(a+" "+b+" "+c);
}

}
}

C++：

第一次用C++写，小激动啊

#include "stdio.h"
main()
{
char a,b,c,d;
int i;
scanf("%d",&i);
getchar();
while(i--)
{
scanf("%c%c%c",&a,&b,&c);
getchar();
if (a>b) {d=a;a=b;b=d;}
if (a>c) {d=a;a=c;c=d;}
if (b>c) {d=b;b=c;c=d;}
printf("%c %c %c\n",a,b,c);
}
}

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