LeetCode - Remove Element
2013-09-26 21:49
260 查看
Given an array and a value, remove all instances of that value in place and return the new length.
The order of elements can be changed. It doesn't matter what you leave beyond the new length.
The order of elements can be changed. It doesn't matter what you leave beyond the new length.
int removeElement(int A[], int n, int elem) { // Start typing your C/C++ solution below // DO NOT write int main() function int rt = 0; for (int i = 0; i < n; ++i) { if (A[i] != elem) { A[rt++] = A[i]; } } return rt; }
相关文章推荐
- LeetCode 27: Remove Element
- [leetcode] 【数组】27. Remove Element
- leetcode -- Remove Element
- LeetCode(27)--Remove Element
- [LeetCode] Remove Element
- [LeetCode27]Remove Element
- [置顶] [LeetCode] Remove Element
- LeetCode 27. Remove Element
- leetcode第一刷_Remove Element
- leetcode_27_ Remove Element (easy)
- LeetCode(27)-Remove Element
- LeetCode 27. Remove Element
- leetcode-Remove Element
- leetcode--Remove Element
- 【Leetcode】Remove Element (Removing)
- LeetCode27——Remove Element(移除数组中指定的元素)
- LeetCode:Remove Element
- 【LeetCode】算法题 27 Remove Element
- LeetCode 27. Remove Element
- leetcode 刷题之路 86 Remove Element