!!!argc and argv as parameter of main function

Definition

http://stackoverflow.com/questions/3024197/what-does-int-argc-char-argv-mean

argv

and

argc

are how command line arguments are passed to

main()

in C and C++.

argc

will be the number of strings pointed to by

argv

. This will (in practice) be 1 plus the number of arguments, as virtually all implementations will prepend the name of the program to the array.

The variables are named

argc

(argument count) and

argv

(argument vector) by convention, but they can be given any valid identifier:

int main(int num_args, char** arg_strings)

is equally valid.

They can also be omitted entirely, yielding

int main()

, if you do not intend to process command line arguments.

Practice

#include <stdlib.h>

int main(int argc, char* argv[])
{
printf("Have %d arguments", argc);
for (int i = 0; i<argc; ++i) {
printf("%s \n", argv[i]);
}
}

Provide arguments: a1 b2 c3

output is:

Have 4 arguments
./Test               // the full path to the Test project
dsfds
sdf
3
Program ended with exit code: 0

How to provide these parameters in Xcode

http://stackoverflow.com/questions/1454587/passing-arguments-to-main-function