2013 ACM/ICPC Asia Regional Online —— Warmup
2013-09-08 19:05
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1003 Rotation Lock Puzzle
找出每一圈中的最大值即可
代码如下:
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找出每一圈中的最大值即可
代码如下:
#include<iostream> #include<stdio.h> #include<algorithm> #include<iomanip> #include<cmath> #include<cstring> #include<vector> #define ll __int64 #define pi acos(-1.0) #define MAX 50000 using namespace std; bool f[10000005]; int prime[10000005],cnt; void init() { cnt=0; f[1]=1; for(int i=2;i<=10000000;i++){ if(f[i]==0) prime[cnt++]=i; for(int j=0;j<cnt&&i*prime[j]<=10000000;j++){ f[i*prime[j]]=1; if(i%prime[j]==0) break; } } } int main(){ init(); int i,t,n; scanf("%d",&t); while(t--){ scanf("%d",&n); bool flag=0; for(i=0;i<cnt;i++){ if(prime[i]+n>0&&f[prime[i]+n]==0){ flag=1; break; } } if(flag) printf("%d %d\n",prime[i]+n,prime[i]); else puts("FAIL"); } return 0; }
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