hdu 1250-Fibonacci

Hat's Fibonacci

Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)

Total Submission(s): 5890    Accepted Submission(s): 1944


[align=left]Problem Description[/align]
A Fibonacci sequence is calculated by adding the previous two members the sequence, with the first two members being both 1.

F(1) = 1, F(2) = 1, F(3) = 1,F(4) = 1, F(n>4) = F(n - 1) + F(n-2) + F(n-3) + F(n-4)

Your task is to take a number as input, and print that Fibonacci number.

 

[align=left]Input[/align]
Each line will contain an integers. Process to end of file.

 

[align=left]Output[/align]
For each case, output the result in a line.
 

[align=left]Sample Input[/align]

100

 

[align=left]Sample Output[/align]

4203968145672990846840663646 代码： 
#include<stdio.h>
#include<string.h>
int ans[10000][260];
int main()
{
 int n,i,j;
 while(scanf("%d",&n)!=EOF)
 {
  memset(ans,0,sizeof(ans));
  ans[0][0]=ans[1][0]=ans[2][0]=ans[3][0]=1;
  if(n<5)
   printf("1\n");
  else
  {
   for(i=4;i<n;i++)
   {
    for(j=0;j<260;j++)
    {
     ans[i][j]=ans[i-1][j]+ans[i-2][j]+ans[i-3][j]+ans[i-4][j];
    }
    for(j=0;j<260;j++)
    {
     if(ans[i][j]>=100000000)
     {
      ans[i][j+1]+=ans[i][j]/100000000;
      ans[i][j]%=100000000;
     }
    }
   }
   for(j=259;j>=0 && ans[n-1][j]==0;j--) ;
   printf("%d",ans[n-1][j]);
   j--;
   for(;j>=0;j--)
   {
    printf("%08d",ans[n-1][j]);
   }
   printf("\n");
  }
 }
 return 0;
}