[leetcode]Symmetric Tree
2013-08-08 23:32
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有意思的是还要写非递归版本。
这是递归版本:
非递归版本。
这是递归版本:
public class Solution { public boolean isSymmetric(TreeNode root) { // Start typing your Java solution below // DO NOT write main() function if (root == null) return true; return (isMirror(root.left, root.right)); } public boolean isMirror(TreeNode p, TreeNode q) { if (p == null && q == null) return true; if (p != null && q != null && q.val == p.val && isMirror(p.left, q.right) && isMirror(p.right, q.left)) { return true; } return false; } }
非递归版本。
public class Solution { public boolean isSymmetric(TreeNode root) { // Start typing your Java solution below // DO NOT write main() function if (root == null) return true; if (root.left == null && root.right == null) return true; if (root.left == null || root.right == null) return false; LinkedList<TreeNode> lq = new LinkedList<TreeNode>(); LinkedList<TreeNode> rq = new LinkedList<TreeNode>(); lq.offer(root.left); rq.offer(root.right); while (lq.size() != 0 && rq.size() != 0) { TreeNode ln = lq.poll(); TreeNode rn = rq.poll(); if (ln == null && rn == null) continue; if (ln == null || rn == null) return false; if (ln.val != rn.val) return false; lq.offer(ln.left); lq.offer(ln.right); rq.offer(rn.right); rq.offer(rn.left); } return true; } }
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