UVa488 Triangle Wave

Triangle Wave

In this problem you are to generate a triangular wave form according to a specified pair ofAmplitude and Frequency.

Input and Output

The input begins with a single positive integer on a line by itself indicatingthe number of the cases following, each of them as described below. This line isfollowed by a blank line, and there is also a blank line between two consecutiveinputs.

Each input set will contain two integers, each on a separate line. The first integer is the Amplitude; thesecond integer is the Frequency.

For each test case, the output must follow the description below. The outputs oftwo consecutive cases will be separated by a blank line.

For the output of your program, you will be printing wave forms each separated by a blank line.The total number of wave forms equals the Frequency, and the horizontal ``height'' of each waveequals the Amplitude. The Amplitude will never be greater than nine.

The waveform itself should be filled with integers on each line which indicate the ``height'' of thatline.

NOTE: There is a blank line after each separate waveform,
excluding the last one.

Sample Input

1

3
2

Sample Output

1
22
333
22
1

1
22
333
22
1

这题大意就是按照给定的格式（如样例）输出，要注意的只有空行了，在每个样例之间及在每个三角波之间都要有个空行，其他不能有空行。

#include <iostream>
#include <algorithm>
#include <cstring>
#include <cstdio>
#include <cctype>
using namespace std;

int main() {
int Case;
cin >> Case;
while (Case--) {
int a;
int b;
cin >> a >> b;
while (b--) {
for (int i = 1; i <= a; i++) {
for (int j = 1; j <= i; j++) {
cout << i;
}
cout << endl;
}
for (int i = a-1; i > 0; i--) {
for (int j = i; j > 0; j--) {
cout << i;
}
cout << endl;
}
if (b)
cout << endl;
}
if (Case)
cout << endl;
}
return 0;
}