POJ 1458 / HDU 1159 / Southeastern Europe 2003 Common Subsequence (DP&LCS)
2013-07-30 20:06
609 查看
Common Subsequence
http://poj.org/problem?id=1458
Time Limit: 1000MS
Memory Limit: 10000K
Description
A subsequence of a given sequence is the given sequence with some elements (possible none) left out. Given a sequence X = < x1, x2, ..., xm > another sequence Z = < z1, z2, ..., zk > is a subsequence of X if there exists a strictly increasing sequence < i1,
i2, ..., ik > of indices of X such that for all j = 1,2,...,k, xij = zj. For example, Z = < a, b, f, c > is a subsequence of X = < a, b, c, f, b, c > with index sequence < 1, 2, 4, 6 >. Given two sequences X and Y the problem is to find
the length of the maximum-length common subsequence of X and Y.
Input
The program input is from the std input. Each data set in the input contains two strings representing the given sequences. The sequences are separated by any number of white spaces. The input data are correct.
Output
For each set of data the program prints on the standard output the length of the maximum-length common subsequence from the beginning of a separate line.
Sample Input
Sample Output
参考这篇文章。
完整代码:
http://poj.org/problem?id=1458
Time Limit: 1000MS
Memory Limit: 10000K
Description
A subsequence of a given sequence is the given sequence with some elements (possible none) left out. Given a sequence X = < x1, x2, ..., xm > another sequence Z = < z1, z2, ..., zk > is a subsequence of X if there exists a strictly increasing sequence < i1,
i2, ..., ik > of indices of X such that for all j = 1,2,...,k, xij = zj. For example, Z = < a, b, f, c > is a subsequence of X = < a, b, c, f, b, c > with index sequence < 1, 2, 4, 6 >. Given two sequences X and Y the problem is to find
the length of the maximum-length common subsequence of X and Y.
Input
The program input is from the std input. Each data set in the input contains two strings representing the given sequences. The sequences are separated by any number of white spaces. The input data are correct.
Output
For each set of data the program prints on the standard output the length of the maximum-length common subsequence from the beginning of a separate line.
Sample Input
abcfbc abfcab programming contest abcd mnp
Sample Output
4 2 0
参考这篇文章。
完整代码:
/*POJ: 0ms,964KB*/ /*HDU: 31ms,2176KB*/ #include<cstdio> #include<cstring> #include<algorithm> using namespace std; const int maxn = 1010; char a[maxn], b[maxn]; int dp[maxn][maxn]; int main(void) { while (~scanf("%s%s", a, b)) { int lena = strlen(a), lenb = strlen(b); memset(dp, 0, sizeof(dp)); for (int i = 1; i <= lena; ++i) for (int j = 1; j <= lenb; ++j) dp[i][j] = (a[i - 1] == b[j - 1] ? dp[i - 1][j - 1] + 1 : max(dp[i - 1][j], dp[i][j - 1])); printf("%d\n", dp[lena][lenb]); } return 0; }
相关文章推荐
- HDU 1159 & POJ 1458 Common Subsequence(LCS 最长公共子序列O(nlogn))
- hdu 1159 && poj 1458 Common Subsequence (LCS)
- POJ 1458 && HDU 1159 Common Subsequence(LCS)
- hdu 1159 && POJ 1458Common Subsequence(LCS)
- HDU 1159 & POJ 1458 Common Subsequence 【LCS】
- HDU1159 && POJ1458 Common Subsequence (LCS)
- POJ 1458 & HDU 1159 - Common Subsequence(最长公共子序列)
- POJ 1458 Common Subsequence DP LCS 最长公共子序列
- POJ 1458-Common Subsequence(线性dp/LCS)
- POJ1458 Common Subsequence LCS问题入门题[DP]
- Poj 1458 Common Subsequence【LCS】【dp】
- POJ1458 Common Subsequence LCS问题入门题[DP]
- POJ 1458-Common Subsequence(线性dp/LCS)
- POJ 1458 || HDOJ 1159 Common Subsequence (DP)
- HDU/HDOJ 1159/POJ 1458 Common Subsequence(最长公共子序列LCS,滚动数组)
- POJ 1631 / HDU 1950 / ZOJ 1986 / Northwestern Europe 2003 Bridging signals (DP&LIS)
- 杭电1159(Common Subsequence)LCS和dp
- poj 1458 Common Subsequence --- LCS模板
- POJ 1458 && HDU 1159 Common Subsequence (最長公共子序列)dp
- Poj 1458 Common Subsequence(LCS)