C++: byte 和 int 的相互转化

原文链接：http://blog.csdn.net/puttytree/article/details/7825709

typedef unsigned char bt;
typedef unsigned int ui;

void ui2bts(bt* out_pBts, ui in_uiLen) {
if (!out_pBts) {
printf("NULL == out_pBts\n");
return;
}
out_pBts[0] = (bt)(in_uiLen & 0xff);
out_pBts[1] = (bt)((in_uiLen >> 8) & 0xff);
out_pBts[2] = (bt)((in_uiLen >> 16) & 0xff);
out_pBts[3] = (bt)((in_uiLen >> 24) & 0xff);
}

ui bts2ui(bt* in_pBts) {
if (!in_pBts) {
printf("NULL == in_pBts\n");
return 0;
}
ui t_uiResult = (ui)in_pBts[0] & 0xff;
t_uiResult |= (((ui)in_pBts[1] << 8) & 0xff00);
t_uiResult |= (((ui)in_pBts[2] << 16) & 0xff0000);
t_uiResult |= (((ui)in_pBts[3] << 24) & 0xff000000);
return t_uiResult;
}