C#小数保留位数

c#下关于小数位数的一些实现方法集合，方便对c#小数位数控制的朋友。

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1.System.Globalization.NumberFormatInfo provider = new System.Globalization.NumberFormatInfo();

provider.NumberDecimalDigits =intDecLength; //要设定的小数位数

double strCashAmt=Convert.ToDouble(this.txtCashAmt.Text); //先把控件內的值转成double

this.txtCashAmt.Text = strCashAmt.ToString("N",provider); //再利用ToString函数格式化小数位数

2.保留N位,四舍五入 .

decimal d= decimal.Round(decimal.Parse("0.55555"),2);

3.保留N位四舍五入

Math.Round(0.55555,2)

4,保留N位四舍五入

double dbdata = 0.55555;

string str1 = dbdata.ToString("f2");//fN 保留N位，四舍五入

5.保留N位四舍五入

string result = String.Format("{0:N2}", 0.55555);//2位

string result = String.Format("{0:N3}", 0.55555);//3位

6. 保留N位四舍五入 (不错)

double s=0.55555;

result=s.ToString("#0.00");//点后面几个0就保留几位

C#下如果显示保留小数位数，及百分号的解决方法:

1、用NumberFormatInfo类来解决:

System.Globalization.NumberFormatInfo provider = new System.Globalization.NumberFormatInfo();

provider.PercentDecimalDigits = 2;//小数点保留几位数.

provider.PercentPositivePattern = 2;//百分号出现在何处.

double result = (double)1 / 3;//一定要用double类型.

Response.Write(result.ToString("P", provider));

2、用toString方法.:

public string getRate(double hcount, double task)

{

string rValue;

string temp = "";

if (task == 0)

{

task = 1;

}

double db = (hcount / task) * 100;

if (hcount >= task)

{

rValue = "100%";

}

else

{

rValue = db.ToString("#0.#0") + "%";

}

return rValue;

}

string str1 = String.Format("{0:N1}",56789); //result: 56,789.0

string str2 = String.Format("{0:N2}",56789); //result: 56,789.00

string str3 = String.Format("{0:N3}",56789); //result: 56,789.000

string str8 = String.Format("{0:F1}",56789); //result: 56789.0

string str9 = String.Format("{0:F2}",56789); //result: 56789.00

string str11 =(56789 / 100.0).ToString("#.##"); //result: 567.89

string str12 =(56789 / 100).ToString("#.##"); //result: 567

详细出处参考：http://www.jb51.net/article/17010.htm