Ural-1001. Reverse Root(水题)

1001. Reverse Root
Time limit: 2.0 second
Memory limit: 64 MB
The problem is so easy, that the authors were lazy to write a statement for it!
Input
The input stream contains a set of integer numbers Ai (0 ≤ Ai ≤ 1018). The numbers are separated by any number of spaces and line breaks. A size of the input stream does not exceed 256 KB.
Output
For each number Ai from the last one till the first one you should output its square root. Each square root should be printed in a separate line with at least four digits after decimal point.
Sample
input
output
[code] 1427  0

876652098643267843
5276538
2297.0716
936297014.1164
0.0000
37.7757
[/code]
题意：输入一个数字集合，按照输入顺序的逆序给出数字的平方根
思路：用Vector保存输入数据，从后往前遍历
#include <iostream>
#include <cstdio>
#include <vector>
#include <algorithm>

using namespace std;
vector<double>v;
int main()
{
double a;
int cnt=0;
//    freopen("in.txt","r",stdin);
while(scanf("%lf",&a)!=EOF)
{
//        printf("%lf ",a);
v.push_back(sqrt(a));
}
//    printf("\n");
for(int i=v.size()-1;i>=0;i--)
{
printf("%.4lf\n",v[i]);
}
return 0;
}