Length of Last Word

Q: Given a string s consists of upper/lower-case alphabets and empty space characters

' '

, return the length of last word in the string.

If the last word does not exist, return 0.

Note: A word is defined as a character sequence consists of non-space characters only.

For example,
Given s =

"Hello World"

,
return

5

.

A: length记录当前单词长度（空格看做长度为0），prevLength记录（前一个单词长度）。

如果length>0, 最后一个单词长度为length，否则为prevLength;

给prevLength赋值的时候要考虑空格连续的情况：如果length = 0, 说明遇到连续空格，不应该给prevLength赋值。

int lengthOfLastWord(const char *s) {
// Start typing your C/C++ solution below
// DO NOT write int main() function
int length = 0;
int  prevLength = 0;
const char *cur = s;
while(*cur!='\0')
{
if(*cur!=' ')
length++;
else
{
prevLength = (length>0?length:prevLength);
length = 0;
}

cur++;
}

return (length>0?length:prevLength);
}