Codeforces Round #138 (Div. 2) A题
2013-06-07 19:46
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这题的意思就是:给你一个每个面为矩形的平行六面体,告诉你交于一点的三个面的面积x,y,z,问题这个平行六面体的边长和是多少。其实这个平行六面体就是矩形!这样就很好做了!
代码如下:
#include <iostream>
#include <cstdio>
#include <cmath>
using namespace std;
int main()
{
int x,y,z;
double a,b,c;
while(scanf("%d%d%d",&x,&y,&z)!=EOF)
{
c=sqrt((z*x*1.0)/y);
a=x*1.0/c;
b=z*1.0/c;
printf("%d\n",(int)(4*(a+b+c)));
}
return 0;
}
代码如下:
#include <iostream>
#include <cstdio>
#include <cmath>
using namespace std;
int main()
{
int x,y,z;
double a,b,c;
while(scanf("%d%d%d",&x,&y,&z)!=EOF)
{
c=sqrt((z*x*1.0)/y);
a=x*1.0/c;
b=z*1.0/c;
printf("%d\n",(int)(4*(a+b+c)));
}
return 0;
}
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