[LeetCode]Reverse Integer
2013-05-31 10:39
387 查看
class Solution { public: int reverse(int x) { // Start typing your C/C++ solution below // DO NOT write int main() function int sign = 1; if(x < 0) sign = -1; unsigned int num = x < 0 ? -x : x; int ans = 0; while (num != 0) { ans = ans*10 + num%10; num /= 10; } return ans*sign; } };
相关文章推荐
- 【LeetCode7】【Reverse Integer】java中整形正负表示的一些思考
- Leetcode 7 Reverse Integer 数论
- 《leetcode》reverse-integer
- leetcode 104: Reverse Integer
- LeetCode Palindrome Number && Reverse Integer 解法集合
- LeetCode Reverse Integer
- LeetCode——Reverse Integer
- [LeetCode] Reverse Integer、Palindrome Number
- LeetCode 第 7 题(Reverse Integer)
- 【LeetCode】- Reverse Integer(将一个整数反转)
- 【LeetCode 7: Reverse Integer】
- LeetCode:Reverse Integer
- LeetCode: Reverse Integer,Palindrome Number
- Leetcode|Reverse Integer(string转char*总结)
- leetcode Reverse Integer 007
- leetcode第七题:Reverse Integer
- LeetCode : Reverse Integer
- Reverse Integer -leetcode
- Reverse Integer--LeetCode(Java)
- Reverse Integer Leetcode Python Java