poj2390(水题)

http://poj.org/problem?id=2390

Bank Interest

Time Limit: 1000MS		Memory Limit: 65536K
Total Submissions: 12459		Accepted: 7415

Description

Farmer John made a
profit last year! He would like to invest it well but wonders how
much money he will make. He knows the interest rate R (an integer
between 0 and 20) that is compounded annually at his bank. He has
an integer amount of money M in the range 100..1,000,000. He knows
how many years Y (range: 0..400) he intends to invest the money in
the bank. Help him learn how much money he will have in the future
by compounding the interest for each year he saves. Print an
integer answer without rounding. Answers for the test data are
guaranteed to fit into a signed 32 bit integer.
Input

* Line 1: Three
space-separated integers: R, M, and Y
Output

* Line 1: A single
integer that is the number of dollars FJ will have after Y
years.
Sample Input

5 5000 4

Sample Output

6077

Hint

INPUT DETAILS:

5% annual interest, 5000 money, 4 years

OUTPUT DETAILS:

Year 1: 1.05 * 5000 = 5250

Year 2: 1.05 * 5250 = 5512.5

Year 3: 1.05 * 5512.50 = 5788.125

Year 4: 1.05 * 5788.125 = 6077.53125

The integer part of 6077.53125 is 6077.
Source

USACO 2004 November



Source Code

#include<stdio.h>
int main()
{
        double sum;
        int R,M,Y;
        int i;
        while(scanf("%d %d %d",&R,&M,&Y)!=EOF)
        {
                double s=1.0;
                sum=1.0;
                for(i=1;i<=Y;i++)
                {
                        sum*=(double)(1.0+(double)R/100.0);       
                }
                s*=sum*M;
                printf("%d\n",(int)s);
        }
        return 0;
}