cf:B-QR code
2013-05-30 00:12
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B. QR codetime limit per test2 secondsmemory limit per test256 megabytesinputstandard inputoutputstandard outputInputThe input contains two integers a1, a2 (0 ≤ ai ≤ 32),separated by a single space.OutputOutput a single integer.Sample test(s)input
1 1output
0input
3 7output
0input
13 10output
1解题报告:把二维码里的表响应位置输出来参考代码:
#include <stdio.h>#include <string.h>#include <iostream>#include <cmath>#include<string>using namespace std;string s2[33]={"111111101010101111100101001111111","100000100000000001010110001000001","101110100110110000011010001011101","101110101011001001111101001011101","101110101100011000111100101011101","100000101010101011010000101000001","111111101010101010101010101111111","000000001111101111100111100000000","100010111100100001011110111111001","110111001111111100100001000101100","011100111010000101000111010001010","011110000110001111110101100000011","111111111111111000111001001011000","111000010111010011010011010100100","101010100010110010110101010000010","101100000101010001111101000000000","000010100011001101000111101011010","101001001111101111000101010001110","101101111111000100100001110001000","000010011000100110000011010000010","001101101001101110010010011011000","011101011010001000111101010100110","111010100110011101001101000001110","110001010010101111000101111111000","001000111011100001010110111110000","000000001110010110100010100010110","111111101000101111000110101011010","100000100111010101111100100011011","101110101001010000101000111111000","101110100011010010010111111011010","101110100100011011110110101110000","100000100110011001111100111100000","111111101101000101001101110010001"};int main(){int m,n,i;while(cin>>m>>n){cout<<s2[m]<<endl;}return 0;}
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