s3c6410下移植sqlite3.7.8

http://blog.chinaunix.net/uid-30441-id-2133838.html

1、下载源代码http://www.sqlite.org/download.html

2、tar -zxvf sqlite-amalgamation-3.6.23.1.tar.gz

3、进入sqlite-3.6.23.1

4、mkdir build

5、cd build

6、../configure --host=arm-linux --prefix=/usr/local/sqlite3

注意：使用arm-linux-gcc 3.4.5时出现如下错误

checking for C compiler default output file name...

configure: error: C compiler cannot create executables

See `config.log' for more details.

怀疑没有写权限，使用如下配置通过

sudo ../configure --host=arm-linux --prefix=/usr/local/sqlite3

移植到开发板上无法运行，使用下面配置

../configure --host=arm-unknown-linux-gnu --prefix=/usr/local/sqlite3

7、make

出现问题：

arm-none-linux-gnueabi-gcc: 3.6.23.1": No such file or directory

<command-line>: warning: missing terminating " character

^Cmake: *** [sqlite3.lo] 错误 1

解决：

Makefile中

-DPACKAGE_STRING=\"sqlite\ 3.6.23.1\"

改为：

-DPACKAGE_STRING=\"sqlite_3.6.23.1\"

8、sudo make install

出现问题：

arm-linux-ranlib /usr/local/sqlite3/lib/libsqlite3.a

./libtool: line 6619: arm-linux-ranlib: command not found

make[1]: *** [install-libLTLIBRARIES] 错误 127

make[1]:正在离开目录 `/work/development/sqlite/sqlite-3.6.23.1/build'

make: *** [install-am] 错误 2

原因：root权限的时候没有设置arm-linux 的PATH

解决：

su 根用户登录

export PATH=$PATH:/work/tools/arm/bin

make install

9、cd /usr/local/sqlite3

10、cp -arf bin include lib /work/nfs_root/sqlite/ 复制到nfs共享文件夹下

11、mount -t nfs -o intr,nolock,rsize=1024,wsize=1024 192.168.

0.128:/work/nfs_root /mnt/nfs/ mount nfs文件系统

12、cp /mnt/nfs/sqlite/bin/* /usr/bin/

mkdir /usr/lib

cp -arf /mnt/nfs/sqlite/lib/* /usr/lib/

mkdir /usr/include

cp /mnt/nfs/sqlite/include/* /usr/include/

13、开发板上创建数据库

# /usr/bin/sqlite3 demo

SQLite version 3.6.23.1

Enter ".help" for instructions

Enter SQL statements terminated with a ";"

sqlite> create table tbl_demo(uid int, uname varchar(20));

sqlite> insert into tbl_demo values(1, 'jimmy');

sqlite> insert into tbl_demo values(2, 'srp');

sqlite> .quit

14、编写测试程序test.c

#include <stdio.h>
#include <stdlib.h>
#include "sqlite3.h"

static int callback(void *NotUsed, int argc, char **argv, char **azColName)
{
int i;

for(i=0; i<argc; i++) {
printf("%s = %s\n", azColName[i], argv[i] ? argv[i] : "NULL");
}

printf("\n");

return 0;
}

int main(int argc, char **argv)
{
sqlite3 *db;
char *zErrMsg = 0;
int rc;

if( argc!=3 ){
fprintf(stderr, "Usage: %s DATABASE SQL-STATEMENT\n", argv[0]);
exit(1);
}

rc = sqlite3_open(argv[1], &db);
if( rc ){
fprintf(stderr, "Can't open database: %s\n", sqlite3_errmsg(db));
sqlite3_close(db);
exit(1);
}

rc = sqlite3_exec(db, argv[2], callback, 0, &zErrMsg);
if( rc!=SQLITE_OK ){
fprintf(stderr, "SQL error: %s\n", zErrMsg);
sqlite3_free(zErrMsg);
}

sqlite3_close(db);

return 0;
}

15、编译

arm-linux-gcc test.c -I /usr/local/sqlite3/include -L /usr/local/sqlite3/lib -lsqlite3 -o test

16、将test拷贝到开发板与数据库demo同一个目录下

sqlite

demo

test

17、运行

# ./test demo "select * from tbl_demo"

uid = 1

uname = jimmy

uid = 2

uname = srp

18、sqlite移植成功

注意：

＃gcc test.c -I /usr/local/sqlite3/include -L /usr/local/sqlite3/lib -lsqlite3 -o test

/usr/bin/ld: skipping incompatible /usr/local/sqlite3/lib/libsqlite3.so when searching for -lsqlite3

/usr/bin/ld: skipping incompatible /usr/local/sqlite3/lib/libsqlite3.a when searching for -lsqlite3

/usr/bin/ld: cannot find -lsqlite3

collect2: ld 返回 1

原因：sqlite是使用arm-linux-gcc编译的，所以使用的gcc与arm-linux-gcc不兼容