排名 Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others) Total Submiss
2013-05-22 18:12
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今天的上机考试虽然有实时的Ranklist,但上面的排名只是根据完成的题数排序,没有考虑 每题的分值,所以并不是最后的排名。给定录取分数线,请你写程序找出最后通过分数线的 考生,并将他们的成绩按降序打印。 |
[align=left]Input[/align] 测试输入包含若干场考试的信息。每场考试信息的第1行给出考生人数N ( 0 < N < 1000 )、考题数M ( 0 < M < = 10 )、分数线(正整数)G;第2行排序给出第1题至第M题的正整数分值;以下N行,每行给出一 名考生的准考证号(长度不超过20的字符串)、该生解决的题目总数m、以及这m道题的题号 (题目号由1到M)。 当读入的考生人数为0时,输入结束,该场考试不予处理。 |
[align=left]Output[/align] 对每场考试,首先在第1行输出不低于分数线的考生人数n,随后n行按分数从高 到低输出上线考生的考号与分数,其间用1空格分隔。若有多名考生分数相同,则按他们考 号的升序输出。 |
[align=left]Sample Input[/align]4 5 25 10 10 12 13 15 CS004 3 5 1 3 CS003 5 2 4 1 3 5 CS002 2 1 2 CS001 3 2 3 5 1 2 40 10 30 CS001 1 2 2 3 20 10 10 10 CS000000000000000001 0 CS000000000000000002 2 1 2 0 |
[align=left]Sample Output[/align]3 CS003 60 CS001 37 CS004 37 0 1 CS000000000000000002 20 <div style="" border-bottom:="" #b7cbff="" 1px="" dashed;="" border-left:="" padding-bottom:="" 6px;="" padding-left:="" padding-right:="" font-family:="" times"="">Hint Huge input, scanf is recommended. |
[align=left]Source[/align] 浙大计算机研究生复试上机考试-2005年 |
[align=left]Recommend[/align] JGShining |
#include<cstdio> #include<algorithm> #include<cstring> using namespace std; struct student { char code[21]; int score; }stu[1000]; int cmp(struct student a,struct student b) { if(a.score!=b.score) { return a.score>b.score; } else { return strcmp(a.code,b.code)<0; } } int main() { int N,M,G,m,a[15],i,j,sum,tmp,count; while(~scanf("%d",&N),N) { scanf("%d%d",&M,&G); for(i=1;i<=M;i++) { scanf("%d",&a[i]); } for(i=0;i<N;i++) { scanf("%s",stu[i].code); scanf("%d",&m); for(j=sum=0;j<m;j++) { scanf("%d",&tmp); sum+=a[tmp]; } stu[i].score=sum; } sort(stu,stu+N,cmp); count=0; for(i=0;i<N;i++) { if(stu[i].score>=G) count++; } printf("%d\n",count); for(i=0;i<N;i++) { if(stu[i].score>=G) { printf("%s %d\n",stu[i].code,stu[i].score); } } } return 0; }
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