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uva127 ``Accordian'' Patience ——链表模拟题

2013-05-13 19:10 295 查看
题目链接:http://uva.onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=103&page=show_problem&problem=63

题目大意:神牛讲的很清楚~http://blog.csdn.net/camelwombat/article/details/5949508 感觉还是首先要读懂题目意思,这个也是有难度的

题目思路:

  用数组模拟链表,考的是代码能力,关键是逻辑关系搞清楚,然后再敲,再就是细节问题,代码有一点小错就需要调很久。

参考这位神牛的思路写的……/article/2505341.html

#include <iostream>
#include <cstdio>
#include <cstdlib>
#include <cstring>
#include <cctype>
#include <stack>
#include <queue>
#include <deque>
#include <map>
#include <set>
#include <vector>
#include <cmath>
#include <algorithm>
#define lson l, m, rt<<1
#define rson m+1, r, rt<<1|1
using namespace std;
typedef long long int LL;
const int MAXN =  0x7fffffff;
const int  MINN =  -0x7fffffff;
const double eps = 1e-9;
const int dir[8][2] = {{0,1},{1,0},{0,-1},{-1,0},{-1,1},
{1,1},{1,-1},{-1,-1}};
typedef struct node{
int len; char rank[54], suit[54];
}node;
node card[54];
void eachmove(int pos, int step) {
int Len = card[pos-step].len, len = card[pos].len;
card[pos-step].suit[Len] = card[pos].suit[len-1];
card[pos-step].rank[Len] = card[pos].rank[len-1];
card[pos-step].len++; card[pos].len--;
}
void moveremain(int pos) {
int i, j;
for (i = pos; card[i+1].len!=0; ++i) {
for (j = 0; j < card[i+1].len; ++j) {
card[i].suit[j] = card[i+1].suit[j];
card[i].rank[j] = card[i+1].rank[j];
}
card[i].len = card[i+1].len;
}
}
int solve() {
int i, cnt =52, len, Len;
char suit, rank;
bool mrk, flag;
while (1) {
flag = false;
for (i= 1; i < cnt;++i) {
len = card[i].len;
suit = card[i].suit[len-1];
rank = card[i].rank[len-1];
mrk = false;
if (i >= 3)  {
Len = card[i-3].len;
if (suit == card[i-3].suit[Len-1] || rank== \
card[i-3].rank[Len-1]) {
eachmove(i, 3);
if (card[i].len==0) {
moveremain(i);
cnt--; card[cnt].len = 0;
}
mrk = flag = true;
}
}
if (!mrk && i >= 1) {
Len = card[i-1].len;
if (suit == card[i-1].suit[Len-1] || rank== \
card[i-1].rank[Len-1]) {
eachmove(i, 1);
if (card[i].len==0) {
moveremain(i);
cnt--; card[cnt].len = 0;
}
flag = true;
}
}
if (flag) break;
}
if (!flag) break;
}
return cnt;
}
int main(void){
#ifndef ONLINE_JUDGE
freopen("uva127.in", "r", stdin);
#endif
int i, j;
while (1) {
scanf("%c", &card[0].rank[0]);
if (card[0].rank[0] == '#') break;
scanf("%c", &card[0].suit[0]);
card[0].len = 1;
for (i = 1; i < 52; ++i) {
getchar();
scanf("%c%c", &card[i].rank[0], &card[i].suit[0]);
card[i].len = 1;
}
card[52].len = 0;
int cnt = solve();
if (cnt > 1) printf("%d piles remaining:", cnt);
else printf("%d pile remaining:", cnt);
for (j = 0; j < cnt; ++j) printf(" %d", card[j].len);
printf("\n");
getchar();
}

return 0;
}


这种题目,非常锻炼代码的准确度什么的……
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