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hdu1087Super Jumping! Jumping! Jumping!【动态规划】

2013-05-11 15:06 190 查看
#include <iostream>
using namespace std;

//题意:求一个数组的严格的递增序列最大和
//动态方程:dp[i] = max(dp[i], dp[j] + heigh[i]) , 1<= j<=i, heigh[j] <= heigh[j]

#define NSIZ 100010
int heigh[NSIZ];
int dp[NSIZ];
int main()
{
int i, j, n;
int sum = 0;
while(scanf("%d", &n) != EOF && n)
{
for(i = 1;i <= n; ++i)
{
scanf("%d", &heigh[i]);
dp[i] = heigh[i];
}

dp[0] = 0;
sum  = -1;

for(i = 1;i <= n; ++i)
{
for(j = 1;j <= i; ++j)
{
if(heigh[j] < heigh[i])
{
dp[i] = max(dp[i], dp[j] + heigh[i]);
}
}

if(sum < dp[i])
{
sum = dp[i];
}
}
printf("%d\n", sum);

}

return 0;
}
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