hdu 1847(博弈)
2013-05-09 23:32
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题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=1847
思路:首先我们知道3是必败点,然后类似于巴什博弈,直接对n%3考虑就行了。
View Code
思路:首先我们知道3是必败点,然后类似于巴什博弈,直接对n%3考虑就行了。
View Code
#include<iostream> #include<cstdio> using namespace std; int main(){ int n; while(~scanf("%d",&n)){ n%3==0?puts("Cici"):puts("Kiki"); } return 0; }
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