您的位置:首页 > 其它

poj_2777_线段树

2013-05-02 10:27 225 查看
题目描述:

   在离散段上上色。求覆盖区域的颜色有几种。

 

解题思路:

  
基础线段树的建树+修改+查询的过程。注意查询并不一定要找到区间相等,只要包含区间并且有标志颜色即可。修改函数需要注意标记下移的时候需要注意是否原先已经有标记颜色。

ps:注意,a可能大于b

 

代码:

#include

#include

#define L 100001

#define T 31

typedef struct{

   int left, right;

   int value;

}SEGNODE;

SEGNODE seg_tree[5*L];

int c[T],l,t,o;

void buildSegTree(int l, int r, int index){

   seg_tree[index].left =
l;

   seg_tree[index].right =
r;

   seg_tree[index].value =
0;

  

   if(l!=r){

     
buildSegTree(l,(l+r)/2,2*index);

     
buildSegTree((l+r)/2+1,r,2*index+1);

   }

}

void changeSegTree(int l, int r, int index, int v){

   if(seg_tree[index].left == l
&& seg_tree[index].right == r){

     
seg_tree[index].value = v;

   }else{

     
if(seg_tree[index].value!=0){

         
seg_tree[2*index].value = seg_tree[index].value;

         
seg_tree[2*index+1].value = seg_tree[index].value;

         
seg_tree[index].value = 0;

     
}

     
if(l > (seg_tree[index].left + seg_tree[index].right)/2){

         
changeSegTree(l,r,2*index+1,v);    

     
}else if(r <= (seg_tree[index].left + seg_tree[index].right)/2
){

         
changeSegTree(l,r,2*index,v);

     
}else{

         
changeSegTree(l,(seg_tree[index].left +
seg_tree[index].right)/2,2*index,v);

         
changeSegTree((seg_tree[index].left + seg_tree[index].right)/2+1,
r, 2*index+1,v);

     
}

   }

}

void searchSegTree(int l, int r, int index){

    
if(l >= seg_tree[index].left && r <=
seg_tree[index].right){

        
if(seg_tree[index].value!=0){

           
c[seg_tree[index].value] = 1;

        
}else{

            
if(l > (seg_tree[index].left + seg_tree[index].right)/2){

                
searchSegTree(l,r,2*index+1);

            
}else if(r <= (seg_tree[index].left + seg_tree[index].right)/2
){

                
searchSegTree(l,r,2*index);

            
}else{

                
searchSegTree(l,(seg_tree[index].left +
seg_tree[index].right)/2,2*index);

                
searchSegTree((seg_tree[index].left +
seg_tree[index].right)/2+1,r,2*index+1);

            
}

        
}

    
}

}

main(){

   int
i,j,x,y,color,sum,tmp;

   char oper[2];

  

   scanf("%d %d %d",&l,
&t, &o);

   buildSegTree(1,l,1);

   seg_tree[1].value = 1;

  

   for(i=1;i<=o;i++){

      
scanf("%s",oper);

      
if(strcmp(oper,"C")==0){

         
scanf("%d %d %d",&x, &y, &color);

         
if(x>y){

            
tmp = x;

            
x = y;

            
y = tmp;

         
}

         
changeSegTree(x,y,1,color);

      
}else{

         
memset(c,0,sizeof(c));

         
scanf("%d %d",&x,&y);

         
if(x>y){

            
tmp = x;

            
x = y;

            
y = tmp;

         
}

         
searchSegTree(x,y,1);

         
sum = 0;

         

         
for(j=1;j<=t;j++)

            
if(c[j]==1){

               
sum ++; 

           
内容来自用户分享和网络整理,不保证内容的准确性,如有侵权内容,可联系管理员处理 点击这里给我发消息
标签: