10055 - Hashmat the Brave Warrior

Hashmat the brave warrior
Input: standard input

Output: standard output



Hashmat is a brave warrior who with his group of young soldiers moves from one place to another to fight against his opponents. Before fighting he just calculates one thing, the difference between his soldier number and the opponent's soldier number. From
this difference he decides whether to fight or not. Hashmat's soldier number is never greater than his opponent.

Input

The input contains two integer numbers in every line. These two numbers in each line denotes the number of soldiers in Hashmat's army and his opponent's army or vice versa. The input numbers are not greater than 2^32. Input is terminated by End of File.



Output

For each line of input, print the difference of number of soldiers between Hashmat's army and his opponent's army. Each output should be in seperate line.

Sample Input:

10 12

10 14

100 200

[b]Sample Output:[/b]

2

4

100

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Shahriar Manzoor

16-12-2000

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#include<stdio.h>

int main()

{

long long int a, b;

while (scanf("%lld%lld", &a, &b) != EOF)

printf("%lld\n", a > b ? a - b : b - a);

return 0;

}

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这个题需要注意的有，Sample Input是来做参考的，输出要注意的东西并未表达完.看题要仔细，Hashmat的人数和敌人的人数的顺序不定.还有注意数据范围！