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uva_10827_Maximum sum on a torus( 普通DP )

2013-04-26 13:03 381 查看
題目:

最大子矩陣,只不過行和列都可以向外延伸

分析:

簡單的DP,略

Code:

#include <set>
#include <map>
#include <cmath>
#include <ctime>
#include <stack>
#include <queue>
#include <deque>
#include <vector>
#include <cstdio>
#include <bitset>
#include <cstdlib>
#include <cstring>
#include <algorithm>
using namespace std;

#define DIR     4
#define DIM     2
#define STATUS  2
#define MAXN    100 + 10
#define oo      (~0u)>>1
#define INF     0x3F3F3F3F
#define REPI(i, s, e)   for(int i = s; i <= e; i ++)
#define REPD(i, e, s)   for(int i = e; i >= s; i --)

static const double EPS = 1e-5;

int n;
int v[MAXN+MAXN][MAXN+MAXN], f[MAXN+MAXN], var[MAXN+MAXN];

inline int dp(int start, int end)
{
int s = 0, rst = -INF;
var[start-1] = 0;
REPI(i, start, end) {
if( var[i-1]+f[i] >= 0 ) {
var[i] = var[i-1]+f[i];
rst = max(rst, var[i]);
}
else {
var[i] = 0;
rst = max(rst, f[i]);
}
}
return rst;
}

int process(int row, int col)
{
int rst = -INF;
REPI(i, 1, n) {
REPI(j, 1, col) {
f[j] = 0;
}
REPI(j, i, i+n-1) {
REPI(k, 1, col) {
f[k] += v[j][k];
}
REPI(k, 1, n) {
rst = max(rst, dp(k, k+n-1));
}
}
}
return rst;
}

void input(void)
{
scanf("%d", &n);
REPI(i, 1, n) {
REPI(j, 1, n) {
scanf("%d", &v[i][j]);
}
}
REPI(i, 1, n) {
REPI(j, n+1, n*2) {
v[i][j] = v[i][j-n];
}
}
REPI(i, n+1, 2*n) {
REPI(j, 1, n*2) {
v[i][j] = v[i-n][j];
}
}
}

int main(int argc, char const *argv[])
{
#ifndef ONLINE_JUDGE
freopen("test.in", "r", stdin);
#endif
int cas;
scanf("%d", &cas);
REPI(k, 1, cas) {
input();
printf("%d\n", process(2*n, 2*n));
}
return 0;
}
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