int a[5]={}, &a+1与(int*)a+1的区别

/*
int a[5]={}, &a+1与(int*)a+1的区别
*/
#include <stdio.h>

int  main()
{
int b, *pb;
char *pb2;
pb = &b + 1;
pb2 = (char*)&b + sizeof(b);
printf("&b=%#x, pb=%#x, pb2=%#x\n", &b, pb, pb2);
printf("Equal=%d\n", (void*)pb == (void*)pb2 );

int a[5]={1,2,3,4,5}, *pa;
char *pa2;
pa = (int*)(&a + 1);
pa2 = (char*)&a + sizeof(a);
printf("\nDiff: &a=%#x, %#x, %#x\n", &a, (int*)&a + 1, &a + 1);	// 两者是有区别的

printf("&a=%#x, pa=%#x, pa2=%#x\n", &a, pa, pa2);
printf("Equal2=%d\n", (void*)pa == (void*)pa2 );

puts("结论: &a + 1 == (char*)&a + sizeof(a)\n");

return 0;
}

运行情况:

[zcm@socket #40]$make
gcc -o a a.c
[zcm@socket #41]$./a
&b=0x22ac7c, pb=0x22ac80, pb2=0x22ac80
Equal=1

Diff: &a=0x22ac68, 0x22ac6c, 0x22ac7c
&a=0x22ac68, pa=0x22ac7c, pa2=0x22ac7c
Equal2=1
结论: &a + 1 == (char*)&a + sizeof(a)

[zcm@socket #42]$