A Famous Music Composer
2013-04-04 00:33
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A Famous Music Composer
时间限制:1000 ms | 内存限制:65535 KB难度:1
描述
Mr. B is a famous music composer. One of his most famous work was his set of preludes. These 24 pieces span the 24 musical keys (there are musically distinct 12 scale notes, and each may use major or minor tonality). The 12 distinct scale notes are:
A | A#=Bb | B | C | C#=Db | D | D#=Eb | E | F | F#=Gb | G | G#=Ab |
between major and minor tonalities. This gives 34 possible keys, of which 24 are musically distinct.
In naming his preludes, Mr. B used all the keys except the following 10, which were named instead by their alternate names:
Ab minor | A# major | A# minor | C# major | Db minor |
D# major | D# minor | Gb major | Gb minor | G# major |
输入Each test case is described by one line having the format "note tonality", where "note" is one of the 17 names for the scale notes given above, and "tonality" is either "major" or "minor" (quotes for
clarify).
输出For each case output the required answer, following the format of the sample.
样例输入
Ab minor D# major G minor
样例输出
Case 1: G# minor Case 2: Eb major Case 3: UNIQUE
题解:就是找相应的替换。好郁闷,我还以为有多复杂。
AC代码:
#include<iostream> #include<string.h> #include<stdio.h> using namespace std; int main() { int j=1; char s[200]; while(gets(s)) { if(s[0]=='A'&&s[1]=='#'){s[0]='B';s[1]='b';printf("Case %d: %s\n",j++,s);} else if(s[0]=='A'&&s[1]=='b'){s[0]='G';s[1]='#';printf("Case %d: %s\n",j++,s);} else if(s[0]=='B'&&s[1]=='b'){s[0]='A';s[1]='#';printf("Case %d: %s\n",j++,s);} else if(s[0]=='C'&&s[1]=='#'){s[0]='D';s[1]='b';printf("Case %d: %s\n",j++,s);} else if(s[0]=='D'&&s[1]=='b'){s[0]='C';s[1]='#';printf("Case %d: %s\n",j++,s);} else if(s[0]=='D'&&s[1]=='#'){s[0]='E';s[1]='b';printf("Case %d: %s\n",j++,s);} else if(s[0]=='E'&&s[1]=='b'){s[0]='D';s[1]='#';printf("Case %d: %s\n",j++,s);} else if(s[0]=='F'&&s[1]=='#'){s[0]='G';s[1]='b';printf("Case %d: %s\n",j++,s);} else if(s[0]=='G'&&s[1]=='b'){s[0]='F';s[1]='#';printf("Case %d: %s\n",j++,s);} else if(s[0]=='G'&&s[1]=='#'){s[0]='A';s[1]='b';printf("Case %d: %s\n",j++,s);} else printf("Case %d: UNIQUE\n",j++); } return 0; }
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