您的位置:首页 > 其它

线段树模板(lazy标记)ZOJ 3686

2013-04-03 23:25 344 查看
题解:先搜索用将树上的点给定时间戳,以此当做该节点的区间。

#include <cstdio>
#include<cstring>
#include<algorithm>
using namespace std;

#define N 150005
bool vis
, check
;
int dep, k, n;

struct treeNode
{
int id;
treeNode *brother;
treeNode *son;
} node
, store
;

struct range
{
int low, high;
} ran
;

struct NODE
{
int l, r, val, upcnt;
} nd[N*3];

#define L(u) (u<<1)
#define R(u) (u<<1|1)

void build ( int u, int l, int r )
{
nd[u].l = l;
nd[u].r = r;
nd[u].val = nd[u].upcnt = 0;
if ( l == r ) return;
int mid = ( l + r ) >> 1;
build ( L(u), l, mid );
build ( R(u), mid+1, r );
}

void down(int u)
{
if(nd[u].upcnt == 1)
{
nd[u].upcnt = 0;
nd[L(u)].upcnt = (nd[L(u)].upcnt + 1) % 2;
nd[L(u)].val = nd[L(u)].r - nd[L(u)].l + 1 - nd[L(u)].val;

nd[R(u)].upcnt = (nd[R(u)].upcnt + 1) % 2;
nd[R(u)].val = nd[R(u)].r - nd[R(u)].l + 1 - nd[R(u)].val;
}
}

void update(int u, int l, int r)
{
if(nd[u].l == l && nd[u].r == r)
{
nd[u].upcnt = (nd[u].upcnt + 1) % 2;
nd[u].val = r - l + 1 - nd[u].val;
return;
}

if(nd[u].l != nd[u].r) down(u);
int mid = ( nd[u].l + nd[u].r ) >> 1;
if ( r <= mid )
update ( L(u), l, r );
else if ( l > mid )
update ( R(u), l, r );
else
{
update ( L(u), l, mid );
update ( R(u), mid+1, r );
}
nd[u].val = nd[L(u)].val + nd[R(u)].val;
}

int query(int u, int l, int r)
{
if(nd[u].l == l && nd[u].r == r)
return nd[u].val;

if(nd[u].l != nd[u].r) down(u);
int mid = ( nd[u].l + nd[u].r ) >> 1;
if ( r <= mid )
return query ( L(u), l, r );
else if ( l > mid )
return query ( R(u), l, r );
else
return query ( L(u), l, mid ) + query ( R(u), mid+1, r );
}

void dfs ( int r )
{
vis[r] = true;
ran[r].low = ++dep; //时间戳从1开始
treeNode *temp = node[r].son;
while ( temp != NULL )
{
if ( vis[ temp->id ] == false )
dfs ( temp->id );
temp = temp->brother;
}
ran[r].high = dep;
}

int main()
{
int m, u, v, i;
while(scanf("%d%d",&n,&m) != EOF)
{
dep = k = 0;
memset(node,NULL,sizeof(node));
memset(store,NULL,sizeof(store));
memset(ran,0,sizeof(ran));
memset(vis,0,sizeof(vis));

for ( i = 2; i <= n; ++i )
{
scanf("%d",&u);
v = i;
if ( node[u].son == NULL )
{
node[u].son = &store[k++];
node[u].son->id = v;
}
else
{
treeNode *temp = &store[k++];
temp->id = v;
temp->brother = node[u].son->brother;
node[u].son->brother = temp;
}
}

dfs(1);
// for(int i = 1; i <= n; i++)
//  printf("@@@ %d %d\n", ran[i].low, ran[i].high);

build(1, 1, dep);
char str[3];
while(m--)
{
scanf("%s %d", str, &u);
if(str[0] == 'q')
printf("%d\n", query(1, ran[u].low, ran[u].high));
else
update(1, ran[u].low, ran[u].high);
}
printf("\n");
}
return 0;
}
内容来自用户分享和网络整理,不保证内容的准确性,如有侵权内容,可联系管理员处理 点击这里给我发消息
标签: