您的位置:首页 > 其它

将日期字符串转换为X月X日形式

2013-04-02 16:43 204 查看
得到的日期字符串为:
2013-04-02 16:47:15
需要将其转换为 4月2日 的形式,实现如下:

// 根据时间来返回显示的时间字符串

- (NSString *)transformTime:(NSString *)timeStr
{
if ([timeStr length]<11) {
return timeStr;
}
NSDateFormatter *formater = [[ NSDateFormatter alloc] init];
NSTimeZone *localzone = [NSTimeZone localTimeZone];
[formater setTimeZone:localzone];
[formater setDateFormat:@"yyyy-MM-dd HH:mm:ss"];
NSDate *modefiTime = [formater dateFromString:timeStr];

NSCalendar *gregorian = [[NSCalendar alloc]
initWithCalendarIdentifier:NSGregorianCalendar];
//设置日期里要获取的单元类型
NSInteger flag = NSYearCalendarUnit |NSMonthCalendarUnit |NSDayCalendarUnit |NSHourCalendarUnit |NSMinuteCalendarUnit |NSSecondCalendarUnit;
NSDateComponents* dc = [[[NSDateComponents alloc] init] autorelease];
dc = [gregorian components:flag fromDate:modefiTime];
//    NSInteger nowHour = [dc hour];
//    NSInteger nowMin = [dc minute];
//    NSInteger nowYear = [dc year];
NSInteger nowMonth = [dc month];
NSInteger nowDay = [dc day];

NSString *time = [NSString stringWithFormat:@"%d月%d日", nowMonth, nowDay];
NSLog(@"time = %@", time);
return time;
}
内容来自用户分享和网络整理,不保证内容的准确性,如有侵权内容,可联系管理员处理 点击这里给我发消息
标签: