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UVALive 4004 Space Beacon

2013-03-27 19:01 363 查看
  先DP预处理出以i开头、长度为j、先升/降(0/1)的序列的个数:d[i][j][0/1]。再数给出的串是第几个串。

// 4004	Space Beacon	Accepted	C++	0.009	2013-03-27 10:52:06
#include<cstdio>
#include<cstring>
#include<cctype>
#include<algorithm>
using namespace std;
const int MAXN = 18+5;
int T, a[MAXN];
long long d[10][MAXN][2];
char s[1<<10];
int main()
{
for (int i = 1; i <= 9; i++)
{
d[i][1][0] = d[i][1][1] = 1;
d[i][2][0] = 9-i;
d[i][2][1] = i-1;
}
for (int j = 3; j <= 18; j++)
for (int i = 1; i <= 9; i++)
{
for (int k = i+1; k <= 9; k++)
d[i][j][0] += d[k][j-1][1];
for (int k = 1; k < i; k++)
d[i][j][1] += d[k][j-1][0];
}
scanf("%d",&T); gets(s);
while (T--)
{
gets(s);
int n = 0;
for (int i = 0; s[i]; i++) if (isdigit(s[i]))
a[n++] = s[i]-'0';
long long ans = 0;
for (int i = 0; i < n; i++)
{
for (int j = 1; j < a[i]; j++)
for (int k = max(3-i, 1); k <= 18-i; k++)
{
if (!i)
ans += d[j][k][0]+d[j][k][1];
else if ((i == 1 && j != a[i-1]) || (i > 1 && ((a[i-2] > a[i-1] && a[i-1] < j) || (a[i-2] < a[i-1] && a[i-1] > j))))
ans += d[j][k][a[i-1] > j ? 0 : 1];
}
if (i >= 3)
ans++;
}
printf("%lld\n", ++ans);
}
return 0;
}
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