找出从三角形顶端走到底端的最大和。

从下面的三角形的顶端开始，向下面一行的相邻数字移动，从顶端到底端的最大总和为23.

3
7 4

2 4 6

8 5 9 3

也就是 3 + 7 + 4 + 9 = 23.

找出从以下三角形的顶端走到底端的最大总和：

75

95 64

17 47 82

18 35 87 10

20 04 82 47 65

19 01 23 75 03 34

88 02 77 73 07 63 67

99 65 04 28 06 16 70 92

41 41 26 56 83 40 80 70 33

41 48 72 33 47 32 37 16 94 29

53 71 44 65 25 43 91 52 97 51 14

70 11 33 28 77 73 17 78 39 68 17 57

91 71 52 38 17 14 91 43 58 50 27 29 48

63 66 04 68 89 53 67 30 73 16 69 87 40 31

04 62 98 27 23 09 70 98 73 93 38 53 60 04 23

public class Test {
public static void main(String[] args) {
int[][] arr = new int[][] { {75 },
{95,64},
{17,47,82},
{18,35,87,10},
{20,04,82,47,65},
{19,01,23,75,03,34},
{88,02,77,73,07,63,67},
{99,65,04,28,06,16,70,92},
{41,41,26,56,83,40,80,70,33},
{41,48,72,33,47,32,37,16,94,29},
{53,71,44,65,25,43,91,52,97,51,14},
{70,11,33,28,77,73,17,78,39,68,17,57},
{91,71,52,38,17,14,91,43,58,50,27,29,48},
{63,66,04,68,89,53,67,30,73,16,69,87,40,31},
{04,62,98,27,23,9,70,98,73,93,38,53,60,04,23}};
int length = arr.length-1;
for(int i = length ;i >= 1  ; i--){//从最后一行开始比较左右两个数大小
for(int j = 1 ; j <= i ; j++){
if(arr[i][j-1] < arr[i][j]){
arr[i-1][j-1] += arr[i][j];
}
else{
arr[i-1][j-1] += arr[i][j-1];
}
}
}
System.out.println(arr[0][0]);//第一个值则为最大总和
}
}