Codeforces Round #174 DIV2
2013-03-18 10:55
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收获了8个hack,本来排名50+,结果C题没有用long long ,错过了一次绝佳的变紫机会...
A题:简单题。快速幂水过。
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A题:简单题。快速幂水过。
View Code
/* Author:Zhaofa Fang Lang:C++ */ #include <cstdio> #include <cstdlib> #include <sstream> #include <iostream> #include <cmath> #include <cstring> #include <algorithm> #include <string> #include <utility> #include <vector> #include <queue> #include <stack> #include <map> #include <set> using namespace std; typedef long long ll; #define DEBUG(x) cout<< #x << ':' << x << endl #define REP(i,n) for(int i=0;i < (n);i++) #define REPD(i,n) for(int i=(n-1);i >= 0;i--) #define FOR(i,s,t) for(int i = (s);i <= (t);i++) #define FORD(i,s,t) for(int i = (s);i >= (t);i--) #define PII pair<int,int> #define PB push_back #define MP make_pair #define ft first #define sd second #define lowbit(x) (x&(-x)) #define INF (1<<30) #define lson l , m , rt << 1 #define rson m + 1 , r , rt << 1 | 1 const int maxn = 200011; ll dp[maxn][2],a[maxn]; int n; bool vist[maxn][2]; ll dfs(int p,int q){ if(p<=0 || p>n)return 0; if(p == 1)return -1; if(vist[p][q])return dp[p][q]; vist[p][q] = 1; int tmp1; if(!q)tmp1 = p + a[p]; else tmp1 = p - a[p]; ll tmp2 = dfs(tmp1,q^1); if(tmp2 == -1)dp[p][q] = -1; else dp[p][q] = tmp2 + a[p]; return dp[p][q]; } int main(){ //freopen("in","r",stdin); //freopen("out","w",stdout); memset(dp,-1,sizeof(dp)); scanf("%d",&n); FOR(i,2,n)scanf("%I64d",a+i); FOR(i,2,n){ if(!vist[i][0])dfs(i,0); if(!vist[i][1])dfs(i,1); } FOR(i,1,n-1) if(dp[i+1][1] == -1)puts("-1"); else printf("%I64d\n",dp[i+1][1]+i); return 0; }
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