POJ 1753 枚举二进制+BFS

#include <iostream>
#include <queue>

using namespace std;

int step[65535];  //记录步骤
bool flag[65535];  //防止重复搜索

unsigned short qState[65535]; //搜索的状态，正好可以用一个16位的无符号短整形表示
int rear = 0; //队列尾指针
int top = 0; //队列头指针

///初始化：读入棋盘初始状态并把它转化为整数存入队列头，黑的位为1白的为0
void Init()
{
unsigned short temp = 0;
char c;

for(int i=0; i < 4; i++)
for(int j = 0; j < 4; j++)
{
cin>>c;
if('b' == c)
temp |= (1<<(i*4+j));
}

qState[rear++] = temp;
flag[temp]  = true;
}

///翻转一个棋子并按规则对齐周围棋子附加影响
unsigned short move(unsigned short state, int i)
{
unsigned short temp=0;
temp |= (1<<i);
if((i+1)%4 != 0) //右，且不在最右边
temp |= (1<<(i+1));
if(i%4 != 0) //左，且不在最左边
temp |= (1<<(i-1));
if(i+4 < 16) //下
temp |= (1<<(i+4));
if(i-4 >= 0) //上
temp |= (1<<(i-4));

return (state ^ temp);
}

//广度优先搜索，从队列中循环取出状态，并把翻转16次（即所有情况），一旦发现满足要求的立即停止，否则加入队列
bool BFS()
{
while(rear > top)
{
unsigned short state = qState[top++];
//qState.pop();
for(int i=0; i < 16; i++)
{
unsigned short temp;
temp = move(state,i);
if(0 == state || 65535 == state)
{
cout<<step[state];
return true;
}
else if(!flag[temp]) //防止重复搜索
{
//qState.push(temp);
qState[rear++] = temp;
flag[temp] = true;
step[temp] = step[state]+1;
}
}
}

return false;
}

int main(void)
{

Init();
if(!BFS()) cout<<"Impossible";

char c;
cin>>c;
}