HDOJ1012 u Calculate e

#include<stdio.h>
void main()
{
int n=0;
double e=1,t=1;//t记录阶乘
char str[65];
printf("n e\n");
printf("- -----------\n");
while(n<=9)
{
printf("%d ",n);
switch(n)
{
case 0:
case 1:
printf("%.0lf\n",e);
break;
case 2:
printf("%.1lf\n",e);
break;
default:
printf("%.9lf\n",e);
break;
}
t*=++n;
e += 1.0/t;
}
}